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Question: The equation of a progressive wave where \[t\] is the time in second \(x\) is the distance in meter ...

The equation of a progressive wave where tt is the time in second xx is the distance in meter is y=Acos240(tx12)y = A\cos 240\left( {t - \dfrac{x}{{12}}} \right). The phase difference (in SI unit) between two position 0.5m0.5m apart is
A.40
B.20
C.10
D.5

Explanation

Solution

We will use the definition of phase difference in this question. The lateral difference between two or more waveforms along a common axis and the same frequency sinusoidal waveforms is known as phase difference. The phase differential equation would therefore be: y=Acos(ωtKx)y = A\cos \left( {\omega t - Kx} \right),where k=k = propagation wave vector, ω=\omega = angular frequency, t=t = time, x=x = position vector, A=A = maximum amplitude.
Formula used:
Δφ=2πλ×Δx\Delta \varphi = \dfrac{{2\pi }}{\lambda } \times \Delta x, where Δx=\Delta x = path difference, and K=2πλK = \dfrac{{2\pi }}{\lambda }.

Complete answer:
According to the question the equation for a progressive wave is y=Acos240(tx12)y = A\cos 240\left( {t - \dfrac{x}{{12}}} \right), where tt is the time in second xx is the distance in meter.
So, we can also write the above equation as follows,
y=Acos(240t240×x12)\Rightarrow y = A\cos \left( {240t - 240 \times \dfrac{x}{{12}}} \right)
y=Acos(240t20x)\Rightarrow y = A\cos \left( {240t - 20x} \right)-------equation (1)
Now if we see the standard equation for the progressive wave, which is as
y=Acos(ωtKx)y = A\cos \left( {\omega t - Kx} \right)---------equation (2)
On comparing the equation (1) and equation (2), we see that
ω=240\omega = 240and K=20K = 20
Now we have to find phase difference, formula for the phase difference is,
Δφ=2πλ×Δx\Delta \varphi = \dfrac{{2\pi }}{\lambda } \times \Delta x------equation (3), where Δx=\Delta x = path difference.
Here it is given in the question, the path difference = Δx=0.5\Delta x = 0.5 and we know that the K=2πλ=20K = \dfrac{{2\pi }}{\lambda } = 20, So putting the values in the equation (3), we get
Δφ=K×Δx\Rightarrow \Delta \varphi = K \times \Delta x
Δφ=K×Δx\Rightarrow \Delta \varphi = K \times \Delta x
Δφ=20×0.5\Rightarrow \Delta \varphi = 20 \times 0.5
Δφ=10\Rightarrow \Delta \varphi = 10
Hence the phase difference (in SI unit) between two positions 0.5m0.5m apart is 1010.

So, option (C) is the correct answer.

Note:
In these types of questions it is best to consider the basic concepts such as progressive waves, i.e. a wave that moves in the same direction continuously in a medium without the change in its amplitude. Let's take one example on a string of a progressive wave. So, here we'll define the displacement relationship of any element on the string as a function of time, and the vibration of the string elements along the length at a given time.