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Question

Physics Question on Waves

The equation of a progressive wave can be given by y=15y=15 sin(660πt0.02πx)cm.\sin (660\pi t-0.02\pi x)\,cm. The frequency of the wave is

A

330 Hz

B

342 Hz

C

365 Hz

D

660 Hz

Answer

330 Hz

Explanation

Solution

Given that y=15sin(660πt0.02πx)y=15\, \sin (660 \pi t-0.02 \pi x)
Comparing with general equation of progressive wave, we get
y=(x,t)=Asin(2πTt2πλx)y=(x, t)=A \sin \left(\frac{2 \pi}{T} t-\frac{2 \pi}{\lambda} x\right)
2πT=660π\therefore \frac{2 \pi}{T}=660 \pi
or 1T=330\frac{1}{T}=330 or v=330Hzv =330\, Hz