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Question

Question: The equation of a plane which cuts equal intercetps of unit length on the axes, is...

The equation of a plane which cuts equal intercetps of unit length on the axes, is

A

x+y+z=0x + y + z = 0

B

x+y+z=1x + y + z = 1

C

x+yz=1x + y - z = 1

D

xa+ya+za=1\frac{x}{a} + \frac{y}{a} + \frac{z}{a} = 1

Answer

x+y+z=1x + y + z = 1

Explanation

Solution

Equation of required plane is, x1+y1+z1=1\frac { x } { 1 } + \frac { y } { 1 } + \frac { z } { 1 } = 1

x+y+z=1\Rightarrow x + y + z = 1.