Question

The equation of a line through the intersection of lines $x=0$ and $y=0$ and through the
point $\left( 2,~2 \right)$ is
(a) $y=x-1$
(a) $y=-x$
(b) $y=x$
(c) $y=-x+2$

Answer 1

Hint: Substitute the given points into the standard equation of line formula.

The equations of the given lines are $x=0$ and $y=0$. The coordinates of the point of
intersections are already available. This means that the point of intersection of these lines would be
$\left( 0,0 \right)$. Another point through which the required line passes through is given in the
question as $\left( 2,2 \right)$.
Now, we know that the equation of a line passing through two points $({{x}_{1}},{{y}_{1}})$ and
$({{x}_{2}},{{y}_{2}})$ is given by,

& y-{{y}_{1}}=m(x-{{x}_{1}}) \\\ & \Rightarrow y-{{y}_{1}}=\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}\times (x-{{x}_{1}}) \\\ \end{aligned}$$ So, the equation of the required line passing through $\left( 0,0 \right)$ and $\left( 2,2 \right)$ can be obtained as, $y-0=\dfrac{2-0}{2-0}\left( x-0 \right)$ Therefore, the equation of the required line is $y=x$. Hence, we get option (c) as the correct answer. Note: The equations $x=0$ and $y=0$ indicate that the required line passes through the origin. So, the formula to find the equation of the line passing through a point $\left( {{x}_{1}},{{y}_{1}} \right)$ can be obtained as $y=mx$, where $m=\dfrac{{{y}_{1}}}{{{x}_{1}}}$ is the slope.