The equation of a line through (3,– 4) and perpendicular to... | MATH - DISTANCE BETWEEN TWO LINES, PERPENDICULAR | SolveeIt | Solveeit

Today, August 18

Question

The equation of a line through (3,– 4) and perpendicular to the line 3x + 4y = 5 is –

A

4x + 3y = 24

B

y – 4 = (x + 3)

C

3y – 4x = 24

D

y + 4 = $\frac { 4 } { 3 }$ (x – 3)

Answer

3y – 4x = 24

Explanation

Solution

3x + 4y = 5 .....(i)

line is perpendicular to the line

(i) is ® 4x–3y+l=0....(ii)

\ line (ii) is passing through the point

P(3,– 4) Ž 4(3) – 3 (– 4) + l = 0

Ž l = – 24 Put in (ii) Ž 4x – 3y = 24