Question

The equation of a line passing through the point of intersection of the lines x + 5y + 7 = 0, 3x + 2y – 5 = 0 and perpendicular to the line 7x + 2y – 5 = 0, is given by

• A. 2x – 7y – 20 = 0
• B. 2x + 7y – 20 = 0
• C. – 2x + 7y – 20 = 0
• D. 2x + 7y + 20 = 0

Answer 1

Answer: (A)

2x – 7y – 20 = 0

Answer 2

Point of intersection of the lines is (3, – 2).

Equation of the line which is $\perp$to the line 7x + 2y –5 = 0 is

2x – 7y + l = 0 ….(i)

For l Ž 2(3) – 7(–2) + l = 0

Ž l = – 20

By (i) Ž 2x – 7y – 20 = 0