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Mathematics Question on Parallel Lines

The equation of a line passing through the origin and parallel to the line r=3i^+4j^5k^+t(2i^j^+7k^),\vec{r} = 3\hat{i} + 4\hat{j} - 5\hat{k} + t(2\hat{i} - \hat{j} + 7\hat{k}), where tt is a parameter, is:
(A) x2=y1=z7\frac{x}{2} = \frac{y}{-1} = \frac{z}{7} (B) r=m(12i^6j^+42k^);\vec{r} = m(12\hat{i} - 6\hat{j} + 42\hat{k}); where mm is the parameter (C) r=(12i^6j^+42k^)+s(0i^0j^+0k^);\vec{r} = (12\hat{i} - 6\hat{j} + 42\hat{k}) + s(0\hat{i} - 0\hat{j} + 0\hat{k}); where ss is the parameter (D) x33=y44=z+50\frac{x - 3}{3} = \frac{y - 4}{-4} = \frac{z + 5}{0} (E) x3=y4=z5\frac{x}{3} = \frac{y}{4} = \frac{z}{5}
Choose the correct answer from the options given below:

A

(A) and (B) only

B

(A), (B) and (C) only

C

(C), (D) and (E) only

D

(A) only

Answer

(A) and (B) only

Explanation

Solution

To find the equation of a line passing through the origin and parallel to the given line, we use the direction vector of the line, which is 2i^j^+7k^2\hat{i} - \hat{j} + 7\hat{k}.

(A) The symmetric form x2=y1=z7\frac{x}{2} = \frac{y}{-1} = \frac{z}{7} represents a line parallel to the given direction vector and passing through the origin.

(B) The vector equation r=m(12i^6j^+42k^)\vec{r} = m(12\hat{i} - 6\hat{j} + 42\hat{k}) is obtained by multiplying the direction vector by a scalar and also passes through the origin.

(C) The form r=(12i^6j^+42k^)+s(0i^0j^+0k^)\vec{r} = (12\hat{i} - 6\hat{j} + 42\hat{k}) + s(0\hat{i} - 0\hat{j} + 0\hat{k}) is incorrect as it introduces an additional term that is not needed for parallelism through the origin.

(D) The given equation does not pass through the origin due to the constants.

(E) This form does not represent a line parallel to the given vector.