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Question: The equation of a circle passing through the point (4, 5) having the centre at (2, 2) is –...

The equation of a circle passing through the point (4, 5) having the centre at (2, 2) is –

A

x2 + y2 + 4x + 4y – 5 = 0

B

x2 + y2 – 4x – 4y – 5 = 0

C

x2 + y2– 4x = 13

D

x2 + y2 – 4x – 4y + 5 = 0

Answer

x2 + y2 – 4x – 4y – 5 = 0

Explanation

Solution

Centre (2, 2)

r = (4−2)2+(5−2)2\sqrt{(4 - 2)^{2} + (5 - 2)^{2}}

= 13\sqrt{13}

(x – 2)2 + (y – 2)2 = 13