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Question: The equation \(\left( P + \frac{a}{V^{2}} \right)(V - b)\) = constant. The units of a is...

The equation (P+aV2)(Vb)\left( P + \frac{a}{V^{2}} \right)(V - b) = constant. The units of a is

A

Dyne×cm5Dyne \times cm^{5}

B

Dyne×cm4Dyne \times cm^{4}

C

Dyne/cm3Dyne/cm^{3}

D

Dyne/cm2Dyne/cm^{2}

Answer

Dyne×cm4Dyne \times cm^{4}

Explanation

Solution

According to the principle of dimensional homogenity [P]=[aV2]\lbrack P\rbrack = \left\lbrack \frac{a}{V^{2}} \right\rbrack

[a]=[P][V2]=[ML1T2][L6]=[ML5T2]\lbrack a\rbrack = \lbrack P\rbrack\lbrack V^{2}\rbrack = \lbrack ML^{- 1}T^{- 2}\rbrack\lbrack L^{6}\rbrack = \lbrack ML^{5}T^{- 2}\rbrack

or unit of a = gmgm × cm5cm^{5} × sec–2= Dyne × cm4