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Physics Question on Dual nature of radiation and matter

The equation λ=1227xnm\lambda=\frac{1227}{ x } nm can be used to find the de-Brogli wavelength of an electron In this equation xx stands for : Where, m=m = mass of electron P=P = momentum of electron K=K = Kinetic energy of electron V=V= Accelerating potential in volts for electron

A

mK\sqrt{m K}

B

P\sqrt{ P }

C

K\sqrt{ K }

D

V\sqrt{ V }

Answer

V\sqrt{ V }

Explanation

Solution

From the given options the correct answer is option (D): V\sqrt{ V }