Question

The equation k = (6.5 × 1012s-1)e-26000K/T is followed for the decomposition of compound A. The activation energy for the reaction is ______ kJ mol-1. [nearest integer]
(Given : R = 8.314 J K-1 mol-1]

Answer 1

The correct answer is 216
$k = Ae^{\frac{-Ea}{RT}}$
$\frac{Ea}{RT} = \frac{26000}{T}$
Ea = 26000 × 8.314
= 216164 J
= 216 kJ