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Question: The equation 3x<sup>2</sup> + 4ax + b = 0 has at least one root in (0,1) if...

The equation 3x2 + 4ax + b = 0 has at least one root in (0,1) if

A

4a + b + 3 = 0

B

2a + b + 1 = 0

C

b = 0, a = – 4/3

D

None

Answer

2a + b + 1 = 0

Explanation

Solution

Let f '(x) = 3x2 + 4ax + b

\ f(x) = x3 + 2ax2 + bx + c

Q it is polynomial \ it is continuous & differentiable & f '(x) = 0 has at least one root in (0, 1)

\ it follow Rolle's theorem in [0, 1]

\ f(0) = f(1) Ž c = 1 + 2a + b + c

Ž 2a + b + 1 = 0