Solveeit Logo
Login

Question

Question: The enthalpy of solution of sodium chloride is 4 KJ \(mol^{- 1}\) and its enthalpy of hydration of i...

The enthalpy of solution of sodium chloride is 4 KJ mol−1mol^{- 1} and its enthalpy of hydration of ions is −784kJmol−1- 784kJmol^{- 1} what will be the lattice enthalpy of sodium chloride?

A

+780kJmol−1+ 780kJmol^{- 1}

B

+394kJmol−1+ 394kJmol^{- 1}

C

+788kJmol−1+ 788kJmol^{- 1}

D

+398kJmol−1+ 398kJmol^{- 1}

Answer

+788kJmol−1+ 788kJmol^{- 1}

Explanation

Solution

: ΔHsol=ΔHlattice+ΔHhyd\Delta H_{sol} = \Delta H_{lattice} + \Delta H_{hyd}

4=ΔHlattice+(−784)4 = \Delta H_{lattice} + ( - 784)

ΔHlattice=4−(−784)=+788kJmol−1\Delta H_{lattice} = 4 - ( - 784) = + 788kJmol^{- 1}