Question

The enthalpy of fusion of water is $1.435\, kcal/mol.$ The molar entropy change for the melting of ice at $0^{\circ}C$ is :

• A. 5.260cal /(molK)
• B. 0.526cal /(molK)
• C. 10.52 cal /(molK)
• D. 21.04 cal /(molK)

Answer 1

Answer: (A)

5.260cal /(molK)

Answer 2

$\Delta S =\frac{\Delta H }{ T }=\frac{1.435 \times 1000}{273}$ $=5.26 \frac{ Cal }{ mol \times k }$