Question
Chemistry Question on Thermodynamics
The enthalpy of combustion of H2, cyclohexene (C6H10) and cyclohexene (C6H12) are -241, -3800 and -3920 kJ per mol respectively. Heat of hydrogenation of cyclohexene is:
-121 kJ per mol
+121 kJ per mol
+484 kJ per mol
-484 kJ per mol
-121 kJ per mol
Solution
Given the equations:
H₂ + 21O₂ → H₂O, ΔH = -241 kJ/mol ……..(1)
C₆H₁₀ + 217O₂ → 6CO₂ + 5H₂O, ΔH = -3800 kJ/mol ……..(2)
C₆H₁₂ + 9O₂ → 6CO₂ + 6H₂O, ΔH = -3920 kJ/mol ……..(3)
Equation (1) and equation (2) are added, and then equation (3) is subtracted to yield the following result:
C₆H₁₂ + H₂ → C₆H₁₂
Calculation of Enthalpy Change for Hydrogenation:
The following formula is used to calculate the enthalpy change for hydrogenation, abbreviated as H Hydrogen:
ΔH Hydrogen = (-241 kJ/mol) + (-3800 kJ/mol) - (-3920 kJ/mol) = -121 kJ/mol
So, the correct option is (A): -121 kJ per mol