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Question: The enthalpies of combustion of carbon and carbon monoxide are – 393.5 and – 283 kJ mol–1 respective...

The enthalpies of combustion of carbon and carbon monoxide are – 393.5 and – 283 kJ mol–1 respectively. The enthalpy of formation of carbon monoxide per mole is

A

110.5 KJ

B

676.5 kJ

C

– 676.5 kJ

D

– 110.5 kJ

Answer

– 110.5 kJ

Explanation

Solution

C(s)+O2(g)CO2(g);ΔC(s) + O_{2}(g) \rightarrow CO_{2}(g);\DeltaH = – 393.5 kJ mol–1

.... (1)

CO(g) + 12\frac{1}{2}O2(g) \rightarrow CO2(g) ; Δ\DeltaH = – 283 kJ mol–1

.... (2)

On subraction equation (2) from equation (1), we get C(s) + O2(g) \rightarrowCO(g) ; Δ\DeltaH = – 110.5 kJ mol–1.

The enthalpy of formation of carbon monoxide per mole = – 110.5 kJ mol–1.