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Question: The engine of a motorcycle can produce a maximum acceleration 5 m/s<sup>2</sup>. Its brakes can prod...

The engine of a motorcycle can produce a maximum acceleration 5 m/s2. Its brakes can produce a maximum retardation 10 m/s2. What is the minimum time in which it can cover a distance of 1.5 km

A

30 sec

B

15 sec

C

10 sec

D

5 sec

Answer

30 sec

Explanation

Solution

If a body starts from rest with acceleration α\alpha and then retards with retardation β\beta and comes to rest. The total time taken for this journey is t and distance covered is S then

S=12αβt2(α+β)=125×10(5+10)×t2S = \frac{1}{2}\frac{\alpha\beta t^{2}}{(\alpha + \beta)} = \frac{1}{2}\frac{5 \times 10}{(5 + 10)} \times t^{2}

1500=125×10(5+10)×t21500 = \frac{1}{2}\frac{5 \times 10}{(5 + 10)} \times t^{2} 6mu6mut=30sec\Rightarrow \mspace{6mu}\mspace{6mu} t = 30\sec.