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Question: The energy stored in an inductor of self inductance L henry carrying a current of *I* ampere is...

The energy stored in an inductor of self inductance L henry carrying a current of I ampere is

A

12L2I\frac{1}{2}L^{2}I

B

12LI2\frac{1}{2}LI^{2}

C

LI2LI^{2}

D

L2IL^{2}I

Answer

12LI2\frac{1}{2}LI^{2}

Explanation

Solution

The energy stored in an inductor is

U=12LI2U = \frac{1}{2}LI^{2}