Question

The energy required to knock out the electron in the third orbit of an atom is equal to –

• A. 13.6 Ev
• B. $\frac{13.6}{9}$eV
• C. – $\frac{13.6}{3}$eV
• D. $\frac{3}{13.6}$eV

Answer 1

Answer: (B)

$\frac{13.6}{9}$eV

Answer 2

E = – $\frac{13.6\mspace{6mu} Z^{2}}{n^{2}}$eV

I.E. = $\frac{13.6\mspace{6mu}}{n^{2}}$Z² eV