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Question

Physics Question on electrostatic potential and capacitance

The energy required to charge a parallel plate condenser of plate separation d and plate area of cross-section A such that the uniform electric field between the plates is E, is

A

12ε0E2Ad \frac{1}{2} \varepsilon_0 E^2 \, Ad

B

12ε0E2/Ad \frac{1}{2} \varepsilon_0 E^2 / Ad

C

ε0E2/Ad \varepsilon_0 E^2 / Ad

D

ε0E2Ad \varepsilon_0 E^2 \, Ad

Answer

ε0E2/Ad \varepsilon_0 E^2 / Ad

Explanation

Solution

Energy required = 12CV2=12ε0E2Ad\frac{1}{2} CV^2 = \frac{1}{2} \varepsilon_0 E^2 \, Ad