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Physics Question on electrostatic potential and capacitance

The energy required to break one bond in DNA is 10−20J10^{-20}J . This value in eV is nearly

A

6

B

0.6

C

0.06

D

0.006

Answer

0.06

Explanation

Solution

Given: The energy required to break one bond in DNA is 10−20J.10^{-20} J.

We know: eV=1.6×10−19 J\text{eV} = 1.6 \times 10^{-19} \, \text{J}

So,
 J=1 eV1.6×10−19 J\, \text{J} = \frac{1 \, \text{eV}}{1.6 \times 10^{-19} \, \text{J}}

Substituting 10−20J:10^{-20} J:

10−20 J=10−20×1 eV1.6×10−19 J=0.0625 eV10^{-20} \, \text{J} = 10^{-20} \times \frac{1 \, \text{eV}}{1.6 \times 10^{-19} \, \text{J}} = 0.0625 \, \text{eV}

Therefore, the energy required to break one bond in DNA is, 0.0625 eV.0.0625\ eV.