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Question

Physics Question on Nuclei

The energy released in the fission of 1kg1 \,kg of 92U235_{92}{{U}^{235}} is (energy per fission = 200 MeV)

A

5.1×1026eV5.1\times {{10}^{26}}eV

B

5.1×1026J5.1\times {{10}^{26}}J

C

8.2×1013J8.2\times {{10}^{13}}J

D

8.2×1013MeV8.2\times {{10}^{13}}MeV

Answer

8.2×1013J8.2\times {{10}^{13}}J

Explanation

Solution

Energy released from 1 kg of uranium =200×106×1.6×1019×6.023×1026235=\frac{200\times {{10}^{6}}\times 1.6\times {{10}^{-19}}\times 6.023\times {{10}^{26}}}{235} =8.2×1013J=8.2\times {{10}^{13}}J