Solveeit Logo

Question

Chemistry Question on Structure of atom

The energy of the second Bohr orbit of the hydrogen atom is -328 kJ mol-1; hence the energy of the fourth Bohr orbit would be:

A

- 41 kJ mol-1

B

-1224 kJ mol-1

C

-284 kJ mol-1

D

-82 kJ mol-1

Answer

-82 kJ mol-1

Explanation

Solution

En =−RH (12n\frac{1}{2n})
As stated: E2 = 328 kJ/mol
E2 = RH (122\frac{1}{22}) = 328 kJmol-1 and E4 = RH (122\frac{1}{22}) (14\frac{1}{4}) = 328 kJ/mol (14\frac{1}{4}) = 82 kJ/mol