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Question: The energy of second Bohr orbit of the hydrogen atom is –328 *kJ mol*<sup>–1</sup>, hence the energy...

The energy of second Bohr orbit of the hydrogen atom is –328 kJ mol–1, hence the energy of fourth Bohr orbit would be

A

– 41 kJ mol–1

B

–1312 kJ mol–1

C

–164 kJ mol–1

D

– 82 kJ mol–1

Answer

– 82 kJ mol–1

Explanation

Solution

E4E2=2242=416=14\frac{E_{4}}{E_{2}} = \frac{2^{2}}{4^{2}} = \frac{4}{16} = \frac{1}{4};E4=E24=3284=82kJ/mol.E_{4} = \frac{E_{2}}{4} = \frac{- 328}{4} = - 82kJ/mol.