Question

The energy of one mole of photons of radiation of frequency 2 $\times$1012 Hz in Jmol-1 is ________ (Nearest integer)

[Given : $h=6.626\times10^{-34}Js$

$N_{A}=6.022\times10^{23}mol^{-1}$]

Answer 1

The correct answer is 798.
For one photon E=hv
For one mole photon,
E=6⋅023×1023×6⋅626×10−34×2×1012
=798⋅16J
≈798J