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Question: The energy of hydrogen atom in *n*th orbit is *E<sub>n</sub>*, then the energy in *n*th orbit of sin...

The energy of hydrogen atom in nth orbit is En, then the energy in nth orbit of singly ionised helium atom will be

A

4En

B

En/4

C

2En

D

En/2

Answer

4En

Explanation

Solution

By using E=13.6Z2n2E = - \frac{13.6Z^{2}}{n^{2}}EHEHe=(ZHZHe)2=(12)2\frac{E_{H}}{E_{He}} = \left( \frac{Z_{H}}{Z_{He}} \right)^{2} = \left( \frac{1}{2} \right)^{2}

EHe=4EnE_{He} = 4E_{n}.