Question
Question: The energy of hydrogen atom in *n*th orbit is *E<sub>n</sub>*, then the energy in *n*th orbit of sin...
The energy of hydrogen atom in nth orbit is En, then the energy in nth orbit of singly ionised helium atom will be
A
4En
B
En/4
C
2En
D
En/2
Answer
4En
Explanation
Solution
By using E=−n213.6Z2 ⇒ EHeEH=(ZHeZH)2=(21)2
⇒ EHe=4En.