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Question: The energy of hydrogen atom in n<sup>th</sup> orbit is E<sub>n</sub>; then the energy in n<sup>th</s...

The energy of hydrogen atom in nth orbit is En; then the energy in nth orbit of singly ionized helium atom will be –

A

4En

B

En4\frac{E_{n}}{4}

C

2En

D

En2\frac{E_{n}}{2}

Answer

4En

Explanation

Solution

En = – 13.6n2\frac{13.6}{n^{2}} eV For H–like atom

En' = 13.6n2\frac{–13.6}{n^{2}}× 22 eV

En' = En × (2)2

En' = 4En