Question

The energy of gamma $(?)$ ray photon is $E_?$ and that of an X-ray photon is $E_x$. If the visible light photon has an energy of $E_v$ , then we can say that

• A. $E_x > E_? > E_v$
• B. $E_? > E_v > E_x$
• C. $E_? > E_x > E_v$
• D. $E_x > E_v > E_?$

Answer 1

Answer: (C)

$E_? > E_x > E_v$

Answer 2

$E_{\gamma} \geq 100 keV$ $E_{X} =100\, eV$ to $100 \,keV$ $E_{v} =2.48\, eV$ So, we can say that $E_{\gamma}>E_{X}>E_{v}$