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Question: The energy of emergent protons in Me V from a cyclotron having radius of its does 1.8 m and applied ...

The energy of emergent protons in Me V from a cyclotron having radius of its does 1.8 m and applied magnetic field 0.7 T is (mass of proton = 1.67×10−27 kg1.67 \times 10 ^ { - 27 } \mathrm {~kg})

A

50

B

60

C

70

D

76

Answer

76

Explanation

Solution

E=q2B2r22mE = \frac { q ^ { 2 } B ^ { 2 } r ^ { 2 } } { 2 m }

=(1.6×10−19)2×(0.7)2×(1.8)22×1.67×10−27=1.22×10−11 J= \frac { \left( 1.6 \times 10 ^ { - 19 } \right) ^ { 2 } \times ( 0.7 ) ^ { 2 } \times ( 1.8 ) ^ { 2 } } { 2 \times 1.67 \times 10 ^ { - 27 } } = 1.22 \times 10 ^ { - 11 } \mathrm {~J}

=76MeV= 76 \mathrm { MeV }