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Question

Question: The energy of electron in first excited state of H-atom is \(- \mspace{6mu} 3.4\mspace{6mu} eV\) its...

The energy of electron in first excited state of H-atom is 6mu3.46mueV- \mspace{6mu} 3.4\mspace{6mu} eV its kinetic energy is.

A

– 3.4 eV

B
  • 3.4 eV
C

– 6.8 eV

D

6.8 eV

Answer
  • 3.4 eV
Explanation

Solution

Kinetic energy = |Total energy|