Question
Chemistry Question on Some basic concepts of chemistry
The energy of electron in 1st orbit of Hydrogen atom is –2.18 × 10-18 Joule. The third ionisation energy of Li+2 ion is
A
(A) 8.72 × 10-18 J
B
(B) 4.36 × 10-18 J
C
(C) 19.62 × 10-18 J
D
(D) 6.54 × 10-18 J
Answer
(C) 19.62 × 10-18 J
Explanation
Solution
Explanation:
III lonisation energy of Li+2 =Z2n2E1H′ where (Z=3,n=1)=−Z2×2.18×10−18n2 Julen=1 for third ionisation.=−(−9×2.18×10−18)=19.62×10−18J