Question

The energy of an electron of de-Broglie wavelength 1Å is –

• A. 150.5 eV
• B. 15.05 Ev
• C. 1.505 eV
• D. 0.1505 eV

Answer 1

Answer: (A)

150.5 eV

Answer 2

l = $\frac{12.27}{\sqrt{V_{0}}}$Å

V = $\frac{12.27 \times 12.27}{1}$ = 150.5 V

Energy E = 150.5 eV