The energy of an electron in the (nth) Bohr orbit of H - ato... | Chemistry | SolveeIt

The energy of an electron in the $nth$ Bohr orbit of H - atom is

$\frac{-13.6}{ n ^{2}} eV$

$\frac{-13.6}{ n } eV$

$\frac{-13.6}{ n ^{4}} eV$

$\frac{-13.6}{n^{3}} e V$

Answer

$\frac{-13.6}{ n ^{2}} eV$

Explanation

$\because\, E_{n}=-13.6 \frac{Z^{2}}{n^{2}} \,eV$ and for hydrogen $(Z=1)$

Therefore, $E_{n}=-\frac{13.6}{n^{2}} \,eV$

Chemistry Question on Structure of atom