test","extracted_subject":"CHEMISTRY","extracted_chapter":"STRUCTURE OF ATOM L","extracted_topic":"BOHR'S MODEL FOR HYDROGEN ATOM ","questionPreviewUrl":"https://cdn.pureessence.tech/question-previews/packed_canvases/canvas_1028.png?top_left_x=532&top_left_y=1351&width=532&height=272&app=solveeit"},"seo_metadata":{"keywords":[]},"doubt_solver_data":{"concept_summary":[]},"embeddings":[],"is_hidden":false,"_id":"66d23cab70136192204c2a6a","slug":"the-energy-of-an-electron-in-the-ist-orbit-of-h-at","content":"The energy of an electron in the Ist orbit of H-atom is— 13.6 eV. The possible energy values of the excited state for electrons in Bohr orbits of Li²⁺ ions is/are-","options":[{"_id":"68a3947e7f15af4716ba4105","text":"–3.4 eV","sequence":0,"isCorrect":false},{"_id":"68a3947e7f15af4716ba4106","text":"–30.6 eV","sequence":1,"isCorrect":false},{"_id":"68a3947e7f15af4716ba4107","text":"–13.6 eV","sequence":2,"isCorrect":false},{"_id":"68a3947e7f15af4716ba4108","text":"Both B & C are correct","sequence":3,"isCorrect":true}],"correct_answer":"Both B & C are correct","explanation":"E_n = –\\(\\frac{13.6Z^{2}}{n^{2}}\\) for Li²⁺, E_n = – \\(\\frac{13.6 \\times 9}{n^{2}}\\)\n\n= \\(\\frac{- 122.4}{n^{2}}\\) eV\n\nIf n = 1 , E_n = – 122.4 eV\n\nIf n = 2 , E_n = – 30.6 eV\n\nIf n = 3 , E_n = – 13.6 eV","question_type":"single_choice","appeared_in":[],"created_at":"2024-08-30T21:42:03.384Z","__v":0,"vector_store_id":"04f918ff-868a-4766-9be4-13f05689087c","updated_at":"2024-08-30T21:42:03.384Z","isStarred":false},"params":{"questionSlug":"the-energy-of-an-electron-in-the-ist-orbit-of-h-at"}}]}]]

Question: The energy of an electron in the Ist orbit of H-atom is— 13.6 eV. The possible energy values of the ...

Solution