Question

The energy of an electron in the first orbit of H- atom is – 13.6 eV. The possible energy values of the excited state for electron in Bohr orbits of Li²⁺ ions is/are –

• A. –3.4 eV
• B. –30.6 eV
• C. –13.6 eV
• D. All of the above

Answer 1

Answer: (D)

All of the above

Answer 2

For Li²⁺, E_n = –13.6 × $\frac{Z^{2}}{n^{2}}$= –13.6 × $\frac{9}{n^{2}}$eV

For n = 2, E₂ = – 13.6 × $\frac{9}{4}$= – 30.6 eV

For n = 3, E₃ = –13.6 × $\frac{9}{9}$= – 13.6 eV

For n = 6, E₆ = –13.6 × $\frac{9}{36}$= – 3.4 eV