Question

The energy of an electron in excited Hydrogen atom is – 3.4 eV. Then, according to Bohr’s Theory, the angular momentum of this electron in J s is –

• A. 2.11 × 10^–34
• B. 3 × 10^–34
• C. 2 × 10^–34
• D. 0.5 × 10^–34

Answer 1

Answer: (A)

2.11 × 10^–34

Answer 2

E_n = – 3.4 eV, E_n µ $\frac{1}{n^{2}}$

E₁ = – 13.6 eV; Clearly n = 2

Angular momentum = $\frac{nh}{2\pi}$ = $\frac{2h}{2\pi}$ = $\frac{h}{\pi}$

= 2.11 × 10^–34 Js