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Question

Question: The energy of a photon is \(p = \frac { h } { \lambda }\), then the velocity of photon will be....

The energy of a photon is p=hλp = \frac { h } { \lambda }, then the velocity of photon will be.

A

E/p

B

Ep

C

(Ep)2\left( \frac { E } { p } \right) ^ { 2 }

D

3×108 m/s3 \times 10 ^ { 8 } \mathrm {~m} / \mathrm { s }

Answer

E/p

Explanation

Solution

Momentum of photon p=Ecp = \frac { E } { c }

\RightarrowVelocity of photon c=Epc = \frac { E } { p }