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Question: The energy of a photon is given as \(3.03 \times 10^{- 19}\) J/atom. The wavelength of the photon is...

The energy of a photon is given as 3.03×10−193.03 \times 10^{- 19} J/atom. The wavelength of the photon is

A

6.56nm6.56nm

B

65.6nm65.6nm

C

0.656nm0.656nm

D

656 nm

Answer

656 nm

Explanation

Solution

: E=hcλE = \frac{hc}{\lambda} or λ=hcE\lambda = \frac{hc}{E}

λ=6.626×10−34Js×3×108ms−13.03×10−19\lambda = \frac{6.626 \times 10^{- 34}Js \times 3 \times 10^{8}ms^{- 1}}{3.03 \times 10^{- 19}}

=6.56×10−7m= 6.56 \times 10^{- 7}m or 656 nm