Question

The energy of a hydrogen atom in its ground state is $- 13.6\mspace{6mu} eV$. The energy of the level corresponding to the quantum number n = 2 (first excited state) in the hydrogen atom is.

• A. – 2.72 eV
• B. – 0.85 eV
• C. – 0.54 eV
• D. – 3.4 eV

Answer 1

Answer: (D)

– 3.4 eV

Answer 2

$E_{n} = \frac{- 13.6}{n^{2}} = \frac{- 13.6}{4} = - 3.4 ⥂ eV$.