Question
Question: The energy liberated on complete fission of 1 kg of \(92U^{235}\) is (Assume 200 MeV energy is liber...
The energy liberated on complete fission of 1 kg of 92U235 is (Assume 200 MeV energy is liberated on fission of 1 nucleus).
A
8.2×1010J
B
8.2×109J
C
8.2×1013J
D
8.2×1016J
Answer
8.2×1013J
Explanation
Solution
Mass of a uranium nucleus
=92×1.6725×10−27+143×1.6747×10−27
=393.35×10−27kg
Number of nuclei in the given mass
=393.35×10−271=2.542×1024
Energy released =200×2.542×1024MeV
=5.08×1026MeV=8.135×1013J=8.2×1013J