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Question: The energy levels of a certain atom for 1st, 2nd and 3rd levels are E, 4E/3 and 2E respectively. A p...

The energy levels of a certain atom for 1st, 2nd and 3rd levels are E, 4E/3 and 2E respectively. A photon of wavelength λ is emitted for a transition 3 → 1. What will be the wavelength of emissions for transition 2 → 1

A

λ/3

B

4λ/3

C

3λ/4

D

Answer

Explanation

Solution

For transition 3 → 1 ΔE=2EE=hcλ\Delta E = 2E - E = \frac{hc}{\lambda}E=hcλE = \frac{hc}{\lambda} …..(i)

For transition 2 → 1 4E3E=hcλ\frac{4E}{3} - E = \frac{hc}{\lambda^{'}}E=3hcλE = \frac{3hc}{\lambda^{'}} …..(ii)

From equation (i) and (ii) λ=3λ\lambda^{'} = 3\lambda