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Question

Physics Question on Atoms

The energy (in eVeV ) required to excite an electron from n=2n=2 to n=4n=4 state in hydrogen atom is

A

0.85-0.85

B

+4.25+4.25

C

3.4-3.4

D

+2.55+2.55

Answer

+2.55+2.55

Explanation

Solution

We know that, En=13.6n2E_{n}=\frac{13.6}{n^{2 \, \, }} eVeV According to question, the required energy is E=E2E4E=E_{2}-E_{4} 13.6(2)213.642=13.6413.616eV\frac{13.6}{\left(\right. 2 \left.\right)^{2}} - \frac{13.6}{4^{2}} = \frac{13.6}{4} - \frac{13.6}{16} \, eV =(13.6×4)13.616=\frac{\left(13.6 \times 4\right) - 13.6}{16} eVeV =40.816=+2.55=\frac{40.8}{16}=+2.55 eVeV