Question

The empirical formula of a compound is $CH_{2}O.$ 0.0835 moles of the compound contains 1.0 g of hydrogen. Molecular formula of the compound is

• A. $C_{2}H_{12}O_{6}$
• B. $C_{5}H_{10}O_{5}$
• C. $C_{4}H_{8}O_{8}$
• D. $C_{3}H_{6}O_{3}$

Answer 1

Answer: (A)

$C_{2}H_{12}O_{6}$

Answer 2

$\because$ 0.0835 mole of compound contains 1gm of hydrogen

$\mathbf{\therefore}$ 1gm mole of compound contain = $\frac{1}{0.0835} = 11.97$

=12gm of hydrogen.

12 gm of $H_{2}$ is present in $C_{2}H_{12}O_{6}$