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Question

Physics Question on radiation

the emission rate of blackbody at 0C0^{\circ}C is R then, the rate of emission at 273C273^{\circ}C is

A

2R

B

4R

C

8R

D

16R

Answer

16R

Explanation

Solution

According Stefan's law, emission rate of a ideal blackbody ET4E \propto T^{4} For T=0C=273KT =0^{\circ} C =273\, K E1(273)4E_{1} \propto(273)^{4} ...(i) For T=273C=273+273=546KT=273^{\circ} C =273+273=546\, K E2(546)4E_{2} \propto(546)^{4} ...(ii) From Eqs. (i) and (ii), E1E2=(273546)4\Rightarrow \frac{E_{1}}{E_{2}}=\left(\frac{273}{546}\right)^{4} RE2=(12)4\Rightarrow \frac{R}{E_{2}}=\left(\frac{1}{2}\right)^{4} (E1=R)\left(\because E_{1}=R\right) Hence, E2=16RE_{2}=16\, R