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Question

Chemistry Question on Electrochemistry

The emf of a galvanic cell, with electrode potential of zinc =+0.76V =+0.76\,V and that of copper =0.34V=0.34\,V , is:

A

0.76 V

B

1.1 V

C

-1,1 V

D

1.6 V

Answer

1.1 V

Explanation

Solution

The emf of a galvanic cell = electrote potential of zinc - electrode potential of copper =0.76(0.34)=1.1V=0.76-(-0.34)=1.1\, V