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Question: The e.m.f E = 4 cos 1000t volts is applied to an L–R circuit containing inductance 3mH and resistanc...

The e.m.f E = 4 cos 1000t volts is applied to an L–R circuit containing inductance 3mH and resistance 4 W . The amplitude of current is –

A

474\sqrt{7}A

B

1.0 A

C

47\frac{4}{7}A

D

0.8 A

Answer

0.8 A

Explanation

Solution

i0 = v0Z\frac{v_{0}}{Z} ,

Z = R2+(ωL)2\sqrt{R^{2} + (\omega L)^{2}}

= 42+(1000×3×103)2\sqrt{4^{2} + (1000 \times 3 \times 10^{–3})^{2}} = 5 W

i0 = 45\frac{4}{5}

i0 = 0.8A