Question

The elongation of a wire on the surface of the earth is 10-4m. The same wire of same dimensions is elongated by 6 × 10-5m on another planet. The acceleration due to gravity on the planet will be ___ ms-2. (Take acceleration due to gravity on the surface of earth = 10 ms-2)

Answer 1

$\Delta I = \frac{M'gI}{2A y}$
⇒$$ Δl ∝ g
⇒$$\frac{g_p}{g_e} = \frac{\Delta I_p}{\Delta I_e} = \frac{6 \times 10^{-5}}{10 \times 10^{-5}}
$⇒$ $g_p = 6 m/s^2 as g_e = 10 m/s^2$