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Question: The element/s present in the \[{4^{th}}\] period is: A.Chlorine B.Iodine C.Fluorine D.Bromin...

The element/s present in the 4th{4^{th}} period is:
A.Chlorine
B.Iodine
C.Fluorine
D.Bromine

Explanation

Solution

A sequential arrangement of elements in a chart, on the basis of atomic number is coined as periodic table. Horizontal rows are called periods and vertical columns are called groups. To approach the question, we should know which elements are present in the fourth period.

Complete answer:
There are a total of seven periods and eighteen groups. In the 4th{4^{th}}period, there are eighteen elements.
They are named as follow:

Name of the elementSymbolAtomic number, Nature
PotassiumKK19, alkali metal
CalciumCaCa20, alkaline earth metal
ScandiumScSc21, transition metal
TitaniumTiTi22, transition metal
VanadiumVV23, transition metal
ChromiumCrCr24, transition metal
ManganeseMnMn25, transition metal
IronFeFe26, transition metal
CobaltCoCo27, transition metal
NickelNiNi28, transition metal
CopperCuCu29, transition metal
ZincZnZn30, metal
GalliumGaGa31, metal
GermaniumGeGe32, metalloid
ArsenicAsAs33, metalloid
SeleniumSeSe34, metalloid
BromineBrBr35, non metal
KryptonKrKr36, radioactive isotopes exist.

From the above table, we get to know that out of the given options, BrBr belongs to period 4.
Thus, option D. Bromine is the correct answer to the given option.
Note:
Period 4 is the first period of the transition series. This period contains elements like Potassium and Calcium which are important from a biological point of view. Bromine, an element belonging to group 17 and period4, is the only non-metal that is liquid at room temperature.Krypton has radioactive isotopes and is used in lighting and photography.