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Question: The element in the first row and third column of the inverse of the matrix \(\begin{bmatrix} 1 & 2 &...

The element in the first row and third column of the inverse of the matrix [123012001]\begin{bmatrix} 1 & 2 & 3 \\ 0 & 1 & 2 \\ 0 & 0 & 1 \end{bmatrix} is

A

1

B

– 2

C

0

D

None of these

Answer

1

Explanation

Solution

a13 of A–1

= C31A\frac{C_{31}}{|A|} = 23121\frac{\left| \begin{matrix} 2 & 3 \\ 1 & 2 \end{matrix} \right|}{1} = 1