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Question

Physics Question on applications of diode

The electrostatic potential due to an electric dipole at a distance rr varies as:

A

1r\frac{1}{r}

B

1r3\frac{1}{r^3}

C

1r2\frac{1}{r^2}

D

rr

Answer

1r2\frac{1}{r^2}

Explanation

Solution

The electrostatic potential V at a point along the axial line of an electric dipole (aligned along the x -axis) is given by:

V=kpcosθr2V = \frac{kp \cos \theta}{r^2}

where: k is Coulomb's constant, p is the dipole moment (p=q×dp = q \times d, where q is the charge and d is the separation distance), r is the distance from the dipole to the point where the potential is being calculated, and θ is the angle between the dipole axis and the line connecting the dipole to the point.

Since the potential V is inversely proportional to r 2, we conclude that the electrostatic potential due to a dipole varies as:

V1r2V \propto \frac{1}{r^2}